P₁V₁ = P₂V₂

Let's use Boyle's Law to calculate the volume of a gas whose initial value is 20 L a 1.0 atm pressure which is compressed to a pressure of 2.0 atm.

P1 = 1.0 atm

V1 = 20 L

P2 = 2.0 atm

Will V2 be larger or smaller than V1?

  Larger     Smaller     Same