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Electrolysis of water using an electrical current

glass outer and innter tubes of electrolysis apparatus

What are the products when water decomposes electrolytically?

thumbnail of entire apparatus

Demonstrating the electrolysis of water requires a specialized piece of glassware, and a source of electrical current. Click here or on the picture to examine this apparatus in more detail.

 

 

 

 

bulbous reservoir and stopcocks

The outer glass tubes and the middle tube are filled with water and the reservoir half filled. Food coloring is usually added so that it is easier to see the liquid in the tubes. In this case, a drop or two of red food color was added.

 

outer and inner tubes, rubber stoppers

Rectangular platinum electrodes attached to a platinum wire are held in position by the rubber stoppers. The platinum wire passes through holes in the rubber stoppers. The platinum electrode are flattened into rectangles to expose as much metal as possible to the reactant (water).

 

alligator clips attached to wires

The platinum wires extending from the rubber stoppers are attached to the power source with aligator clips. Either a dry cell battery or DC current provides enough current to cause the decomposition of water.

 

bubbles in tubes

Once the current is applied, you can see that a reaction is occurring in one of two ways. Bubbles of gas rise from the surface of the electrodes as water decomposes to H2 and O2 gas.

 

three colors of water in tubes

Alternatively, an acid base indicator can indicate that a reaction has occurred. This example contains Universal Indicator, which turns green-blue in base, and pink in acid.

Why are H+ and OH- present since we know that the products of decomposition of water are H2 and O2?

Decompostion of water is a redox reaction. The oxidation reaction occurs at one electrode, and the reduction reaction at the other electrode.

Water is oxidized at the anode. The reaction is...

2H2O ---> O2 + 4H+ + 4e-

Water is reduced at the cathode. The reaction is...

4H2O + 4e- ---> 2H2 + 4OH-

We can tell that the tube on the right has the cathode, since at the cathode H2 is produced. In the decompostion reaction, the volume of H2 produced is twice the volume of O2.

2H2O ---> 2H2 + O2

 

 

 

 

 

 

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